|
|
2. |
y
= -x2 + 2x + 4
x + y = 4 |
|
| Solve
the
linear equation for y. |
y
= -x + 4 |
|
Substitute
in the quadratic equation
Multiply
by -1 to get rid of the
negative sign in front of the x2 term
|
-x + 4=-x2 + 2x + 4
-x = -x2 + 2x
0 = -x2 + 3x
0 = x2 - 3x
0 = x(x - 3)
x = 0 x - 3 = 0
x = 3
|
|
Substitute
each value back into the linear equation. |
x
+ y
= 4
0 + y = 4
y =
4
(0,4)
x + y =
4
3 + y = 4
y =
1
(3,1) |
|
Solution
Set is: |
{(0,4),(3,1)} |
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