Math A
Interior Angles of a Triangle
The sum of the interior angles of any triangle is 180º.
m<M + m<N + m<P = 180º.
The sum of the angles of ANY type of triangle is 180º.
Let x = m<B. Add up all three angles and set them equal to 180º. Solve for x.
Let x = smallest angle 2x = second angle 3x = largest angle
So the smallest angle measures 30º
The base angles are the 2 congruent angles in an isosceles triangle. So, Let x = a base angle
Then x + x + 58 = 180 2x + 58 = 180 2x = 122 x = 61
So a base angle measures 61º.
Murray