Answer to Question 3

3.     

Let c = cost per cat
Let d = cost per dog

164c + 24d = 4240
d = 2c

Solve by any method mentioned.
If done algebraically with substitution:
164c + 24d = 4240
d = 2c

164c + 24(2c) = 4240
164c + 48c = 4240
212c = 4240
c = 20
She can spend $20 on each cat.
d = 2c
d
= 2(20) = 40
She can spend $40 on each dog.

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