Answer to Question 2

2.  

Let x = T/F questions
Let y = Multiple Choice questions

x + y = 20
3x + 11y = 100

Solve by any method mentioned.
If done algebraically:
x
+ y = 20
3x + 11y = 100
3(x + y = 20)
3x + 11 y = 100
3x + 3y = 60
3x + 11y = 100
-8y = -40
8y = 40
y = 5
There are 5 multiple choice questions.
x + 5 = 20
x = 15
There are 15 T/F questions.

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