Let *x* = small pitcher
*y* = large pitcher
2*x* + *y* = 8
*y - x *= 2
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Solve by any method mentioned.
If done algebraically:
2*x* + *y* = 8
__-__*x* + *y* = 2
subtract:
3*x *= 6
*x* = 2
The small pitcher holds 2 cups of water.
2(2) + *y* = 8
4 + *y* = 8
*y* = 4
The large pitcher holds 4 cups of water. |