Visual  Equations Topic Index | Algebra Index | Regents Exam Prep Center
 Here's an idea to try with students who have trouble with abstract concepts, and who might benefit from a more visual approach. (Algebra Tiles can be useful for demonstrating solutions of equations.)

 1. Solve for x:    x + 3 = 7 To solve take the same thing away from both sides - take away 3 ones. So the solution is  x = 4

2. Solve for x:  2x - 3 = x + 2
 To solve, first take away one x from both sides. Then, to remove a red tile on one side, tell the students they have to add a blue tile on the other side. So the solution is  x = 5

3. Solve for x:    4(x + 2) = 2x + 10
 To solve, first take away  2 x's from both sides. Now take away eight  1's from both sides. Now arrange what's left into equal groups on both sides. Therefore, each x = 1.

4. Solve for x:   x + 3 = 11 - 3x
 To solve, first take away three  1's from both sides. Now, to remove a red tile from the right, add a blue tile to the left. Now arrange what's left into equal groups on both sides. Therefore, each x = 2.

 Topic Index | Algebra Index | Regents Exam Prep Center Created by Michael Murray