The scenario is true.
Possible
Proof:
(a + bi)2 = (a + bi)(a + bi) = a2 +abi +abi + b2 i2 = a2 +2abi - b2 = (a2 - b2) + 2abi (a - bi)2 = (a - bi)(a - bi) = a2 -abi -abi + b2 i2 = a2 -2abi - b2 = (a2 - b2) - 2abi (a2 - b2) + 2abi and (a2 - b2) - 2abi are conjugates.
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